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Q: What is the vertex and axis of symmetry of x 4)(x-3)?
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What is the axis of symmetry for the parabola with vertex (-2 -4) and directrix y 1?

The axis of symmetry is x = -2.


Do all functions of the form y equals ax2 have the same vertex and axis of symmetry?

axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES


What is the vertex and the line of symmetry for fx equals 5xsquared?

Vertex = (0,0) Line of symmetry = y axis You should of known that as this function is only X^2


What are the vertex and the axis of symmetry of the equation y equals 2x² plus 4x - 10?

In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)


What are the coordinates of another vertex of the figure A figure has a vertex at (-1 -3). If the figure has line symmetry about the x-axis.?

It is (-1, 3).


Find the vertex and equation of the directri for y2 equals -32x?

y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0


A figure has a vertex at -1 -3 if the figure has line of symmetry about the x-axis what are the coordinates of another vertex of the figure?

2


How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?

By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero


An equation of a parabola that has x equals 2 as its axis of symmetry is?

How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).


Which equation represents the axis of symmetry of the graph of the equation y equals x2-6x 5?

Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.


Fill in the blank The of the vertex of a quadratic equation is determined by substituting the value of x from the axis of symmetry into the quadratic equation?

D


What is the vertex and the axis of symmetry for the function y equals x2 plus 4x plus 1?

Take the derivative: y' = 2x + 4. Set equal to zero: 2x + 4 = 0 --> x = -2. Substitute into original and y = -3. Axis of symmetry is x = -2. Vertex is (-2,-3)