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A figure has a vertex at (-1 -3). If the figure has line symmetry about the y-axis what are the coordinates of another vertex of the figure?
If a figure has line symmetry about the y-axis, then for every point (x, y) on the figure, there is a corresponding point (-x, y). Given that one vertex is at (-1, -3), its symmetric counterpart across the y-axis would be at (1, -3). Thus, the coordinates of another vertex of the figure are (1, -3).
Which letter is key in finding the axis of symmetry?
The key letter in finding the axis of symmetry for a quadratic function in the standard form (y = ax^2 + bx + c) is (b). The axis of symmetry can be calculated using the formula (x = -\frac{b}{2a}), where (a) is the coefficient of (x^2). This formula provides the x-coordinate of the vertex of the parabola, which is also the line of symmetry.
How do you find the equation of a axis of symmetry?
To find the equation of the axis of symmetry for a parabola given in the standard form (y = ax^2 + bx + c), you can use the formula (x = -\frac{b}{2a}). This value of (x) represents the vertical line that divides the parabola into two mirror-image halves. If the parabola is represented in vertex form (y = a(x-h)^2 + k), the axis of symmetry is simply the line (x = h).
How do u find the equation of the axis of symmetry and the vertex of the graph of each function for example y x2-8x-9 Plz help i need to know this?
To find the equation of the axis of symmetry for the quadratic function (y = x^2 - 8x - 9), use the formula (x = -\frac{b}{2a}), where (a = 1) and (b = -8). This gives (x = -\frac{-8}{2 \cdot 1} = 4). The vertex can be found by substituting this (x) value back into the original equation: (y = 4^2 - 8(4) - 9 = 16 - 32 - 9 = -25). Thus, the vertex is at the point ((4, -25)) and the axis of symmetry is the line (x = 4).
What is the formula used to find the axis of symmetry?
The formula to find the axis of symmetry for a quadratic function in the form (y = ax^2 + bx + c) is given by (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. The axis of symmetry passes through the vertex of the parabola and is crucial for graphing the function.
What is the axis of symmetry for the parabola with vertex (-2 -4) and directrix y 1?
The axis of symmetry is x = -2.
Do all functions of the form y equals ax2 have the same vertex and axis of symmetry?
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
What is the vertex and the line of symmetry for fx equals 5xsquared?
Vertex = (0,0) Line of symmetry = y axis You should of known that as this function is only X^2
What are the vertex and the axis of symmetry of the equation y equals 2x² plus 4x - 10?
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
What are the coordinates of another vertex of the figure A figure has a vertex at (-1 -3). If the figure has line symmetry about the x-axis.?
It is (-1, 3).
Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
A figure has a vertex at -1 -3 if the figure has line of symmetry about the x-axis what are the coordinates of another vertex of the figure?
2
How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
A figure has a vertex at (-1 -3). If the figure has line symmetry about the y-axis what are the coordinates of another vertex of the figure?
If a figure has line symmetry about the y-axis, then for every point (x, y) on the figure, there is a corresponding point (-x, y). Given that one vertex is at (-1, -3), its symmetric counterpart across the y-axis would be at (1, -3). Thus, the coordinates of another vertex of the figure are (1, -3).
Which letter is key in finding the axis of symmetry?
The key letter in finding the axis of symmetry for a quadratic function in the standard form (y = ax^2 + bx + c) is (b). The axis of symmetry can be calculated using the formula (x = -\frac{b}{2a}), where (a) is the coefficient of (x^2). This formula provides the x-coordinate of the vertex of the parabola, which is also the line of symmetry.
An equation of a parabola that has x equals 2 as its axis of symmetry is?
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
Which equation represents the axis of symmetry of the graph of the equation y equals x2-6x 5?
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
