The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42
-3x2 = 5 + 3x (add 3x2 to both sides)0 = 3x2 + 5 + 3x or3x2 + 3x + 5 = 0 (since the discriminant is less than zero, we have complex roots)x = [-3 ± √[(32 - 4(3)(5)]]/2(3)x = [-3 ± √(9 - 60)]/6x = (-3 ± √-51)/6x = (-3 ± i√51)/6x = (-3 + i√51)/6 = -1/2 + (√51/6)i orx = (-3 - i√51)/6 = -1/2 - (√51/6)i
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
3x2 + 2x - 56 = 0This is a quadratic equation of the form ax + by + c = 0, where a = 3, b = 2, c = -56.Use the quadratic formula to solve the equation:x = [-b ± √(b2 - 4ac)]/2ax = [-2 ± √[(22 - 4(3)(-56)]]/2(3)x = [-2 ± √(4 + 672)]/6x = (-2 ± √676)/6x = (-2 ± 26)/6x = (-2 + 26)/6 or x = (-2 - 26)/6x = 24/6 or x = -28/6x = 4 or x = -14/3 (as a mixed number, x = - 4 2/3)Thus, the roots of the equation are x = 4 and x = - 14/3.
There is no simplification. It is sqrt(6X +4)There is no simplification. It is sqrt(6X +4)There is no simplification. It is sqrt(6X +4)There is no simplification. It is sqrt(6X +4)
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
-6x + 9x2 - 24 = 3(3x2 - 2x - 8) = 3(3x2 - 6x + 4x - 8) = 3(3x(x - 2) + 4(x - 2)) = 3(3x + 4)(x - 2)
6x(3x2 - x + 4)
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
The operator (+ or -) before the 5 (and before the 6, but that doesn't matter for the discriminant) is missing from the question, so:If it is 3x2 ± 6x + 5, thendiscriminant = (±6)2 - 4 x 3 x 5 = 36 - 60 = -24 If it is 3x2 ± 6x - 5, thendiscriminant = (±6)2 - 4 x 3 x (-5) = 36 + 60 = 96
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
(3x+4)(x-2) 3x2 -6x+4x-8 3x2-2x-8
6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)
-3(x + 2)(x + 4)
False
3x2 + 6x - 24First factor out any common factors of the three terms. In this case, each term is a multiple of 3. So,3x2 + 6x - 24 = 3(x2 + 2x - 8)Next, use the reverse FOIL method to factor the polynomial in the parenthesis (x2 + 2x - 8). x2 factors out to x * x:(x + ??)(x + ??)Now, we must find two numbers that add to get 2 (from the 2x) and multiply to get -8. Those numbers are -2 and 4. So,(x2 + 2x - 8) = (x - 2)(x + 4)So,3x2 + 6x - 24 = 3(x - 2)(x + 4)
The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42