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Q: What is the y-intercept of fx 3x2 6x 4?
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Related questions

Factor x3 plus 3x2-6x-8?

x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)


How do you factor -6x plus 9x2-24?

-6x + 9x2 - 24 = 3(3x2 - 2x - 8) = 3(3x2 - 6x + 4x - 8) = 3(3x(x - 2) + 4(x - 2)) = 3(3x + 4)(x - 2)


How would you factor factor factor 18x to the 3-6x to the 2 plus 24x?

6x(3x2 - x + 4)


Simplify 3x2 plus 2x - 8?

3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).


What is the discriminant value in 3x2 6x 5?

The operator (+ or -) before the 5 (and before the 6, but that doesn't matter for the discriminant) is missing from the question, so:If it is 3x2 ± 6x + 5, thendiscriminant = (±6)2 - 4 x 3 x 5 = 36 - 60 = -24 If it is 3x2 ± 6x - 5, thendiscriminant = (±6)2 - 4 x 3 x (-5) = 36 + 60 = 96


Factor this polynomial completely 3x2 plus 2x - 8?

3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)


Expand the brackets openbracket 3x plus 4 closebracket openbracket x-2 closebracket?

(3x+4)(x-2) 3x2 -6x+4x-8 3x2-2x-8


How do you factor 6x - 6x -16?

6x-6x=0 so all you have left is -16 and there is nothing to factor. I am guessing you meant 6x2 -6x-16 which is 2(3x2 -2x-8) The factor pairs for 8 are 1,8 and 2,4. So let's try 1, 8. We know one of them has to be negative. We see it does not work and when we try 2 and 4 they do not work also. So we cannot factor (3x2 -2x-8) over the integers and we call it prime. The final answer is 2(3x2 -2x-8)


How do you factor -3x2-18x-24?

-3(x + 2)(x + 4)


The polynomial x - 2 is a factor of the polynomial Fx equals 5x2 - 6x plus 4?

False


What is the factored form of 3x2 plus 6x-24?

3x2 + 6x - 24First factor out any common factors of the three terms. In this case, each term is a multiple of 3. So,3x2 + 6x - 24 = 3(x2 + 2x - 8)Next, use the reverse FOIL method to factor the polynomial in the parenthesis (x2 + 2x - 8). x2 factors out to x * x:(x + ??)(x + ??)Now, we must find two numbers that add to get 2 (from the 2x) and multiply to get -8. Those numbers are -2 and 4. So,(x2 + 2x - 8) = (x - 2)(x + 4)So,3x2 + 6x - 24 = 3(x - 2)(x + 4)


What is the product of (3x2 - 2x - 7)(9x2 plus 8x plus 6)?

The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42