Ans:
because of essay calucation in s domine rather than time domine and we take inverse laplace transfom
.....
They are similar. In many problems, both methods can be used. You can view Fourier transform is the Laplace transform on the circle, that is |z|=1. When you do Fourier transform, you don't need to worry about the convergence region. However, you need to find the convergence region for each Laplace transform. The discrete version of Fourier transform is discrete Fourier transform, and the discrete version of Laplace transform is Z-transform.
find Laplace transform? f(t)=sin3t
Fourier transform and Laplace transform are similar. Laplace transforms map a function to a new function on the complex plane, while Fourier maps a function to a new function on the real line. You can view Fourier as the Laplace transform on the circle, that is |z|=1. z transform is the discrete version of Laplace transform.
The type of response given by Laplace transform analysis is the frequency response.
The Laplace transform is related to the Fourier transform, but whereas the Fourier transform expresses a function or signal as a series of modes ofvibration (frequencies), the Laplace transform resolves a function into its moments. Like the Fourier transform, the Laplace transform is used for solving differential and integral equations.
The Laplace transform is used for analyzing continuous-time signals and systems, while the Z-transform is used for discrete-time signals and systems. The Laplace transform utilizes the complex s-plane, whereas the Z-transform operates in the complex z-plane. Essentially, the Laplace transform is suited for continuous signals and systems, while the Z-transform is more appropriate for discrete signals and systems.
.....
The key difference between the Fourier transform and the Laplace transform is the domain in which they operate. The Fourier transform is used for signals that are periodic and have a frequency domain representation, while the Laplace transform is used for signals that are non-periodic and have a complex frequency domain representation. Additionally, the Fourier transform is limited to signals that are absolutely integrable, while the Laplace transform can handle signals that grow exponentially.
They are similar. In many problems, both methods can be used. You can view Fourier transform is the Laplace transform on the circle, that is |z|=1. When you do Fourier transform, you don't need to worry about the convergence region. However, you need to find the convergence region for each Laplace transform. The discrete version of Fourier transform is discrete Fourier transform, and the discrete version of Laplace transform is Z-transform.
Laplace will only generate an exact answer if initial conditions are provided
find Laplace transform? f(t)=sin3t
The key differences between the Laplace transform and the Fourier transform are that the Laplace transform is used for analyzing signals with exponential growth or decay, while the Fourier transform is used for analyzing signals with periodic behavior. Additionally, the Laplace transform includes a complex variable, s, which allows for analysis of both transient and steady-state behavior, whereas the Fourier transform only deals with frequencies in the frequency domain.
Fourier transform and Laplace transform are similar. Laplace transforms map a function to a new function on the complex plane, while Fourier maps a function to a new function on the real line. You can view Fourier as the Laplace transform on the circle, that is |z|=1. z transform is the discrete version of Laplace transform.
The use of the Laplace transform in industry:The Laplace transform is one of the most important equations in digital signal processing and electronics. The other major technique used is Fourier Analysis. Further electronic designs will most likely require improved methods of these techniques.
The type of response given by Laplace transform analysis is the frequency response.
There are continuous functions, for example f(t) = e^{t^2}, for which the integral defining the Laplace transform does not converge for any value of the Laplace variable s. So you could say that this continuous function does not have a Laplace transform.