That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-11 plus or minus the square root of -31) divided by 4.
x = -2.75 + 1.3919410907075054i
x = -2.75 - 1.3919410907075054i
where i is the square root of negative one.
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x(6x - 11)
(x + 13)(2 - x)
x2 - x + 30 does not have any factors. If on the other hand you wanted to factor out: x2 - x - 30 Then it can be done as follows: = x2 - 6x + 5x - 30 = x(x - 6) + 5(x - 6) = (x + 5)(x - 6)
x2 + 18x - 50 does not have rational factors.
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
x2 - 11x + 24 = (x - 3)(x - 8)
x2 -11x-12= (x-12)(x+1)
x^3 - 121x
X2 -11x +10=(x - 1 )(x - 10)
x2 + 11x + 18 (x + 9)(x + 2) CHECK: x2 + 9x + 2x + 18 x2 + 11x + 18 SET EACH EQUAL TO ZERO: x + 9 = 0 x = -9 x + 2 = 0 x = -2 NOW YOU ARE DONE: Solution set: {-9, -2}
21
x2 - 13 + 30 = x2 + 17, which has no real factors.
x^2 + 11x + 6 has no rational zeros.
x(6x - 11)