Two possibilities here. 9x - 30x +25 = -21x + 25 and done, but I don't think you mean that.
9x² - 30x + 25 is more likely.
This is easier than normal, since this follows the square pattern.
(ax-b)² = a²x²-2ab+b²
a² = 9 so a=3
b² = 25 so b=5 3*5*2 = 30, so it checks.
(3x-5)(3x-5) = 9x² -15x - 15x + 25 = 9x² -30x + 25 ■
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-9 plus or minus the square root of 73) divided by 2.
x = -0.2279981273412348
x = -8.772001872658766
No 9xx-18x+36 9(xx-2x+4) xx-2x+4 (doesn't factor evenly)
3x + 1)(3x - 4)
There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2. 9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2 -9x2 - 12x - 4 = -(3x + 2)2 9x2 - 12x + 4 = (3x - 2)2 -9x2 + 12x - 4 = -(3x - 2)2
-28
The same way you'd factor any other similar equation. You're going to run into the complication that the roots of that equation are not real numbers, though; unless you know what complex numbers are, you won't be able to do it.
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
(3x + 4)(3x + 4)
The first equation factors to (3x + 2)(3x + 4) The second equation factors to (3a + 2b)(3a + 4b)
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
is 9x^2 + 4 prime factor
(3x + 4)(3x - 4)
No 9xx-18x+36 9(xx-2x+4) xx-2x+4 (doesn't factor evenly)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
-6x + 9x2 - 24 = 3(3x2 - 2x - 8) = 3(3x2 - 6x + 4x - 8) = 3(3x(x - 2) + 4(x - 2)) = 3(3x + 4)(x - 2)
3x + 1)(3x - 4)
Presumably you mean: 9x2+24x+16? (3x+4)(3x+4)