You CAN'T calculate that, without additional information.
Given the information in the question, AB can have any value whatsoever.
10
10/3
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
20
Not enough information
Ab and Ba are the same line because there are no endpoints to a line. Therefore, you can reverse the order of the letters. So, Cd and Dc are not the same ray because the first letter is the endpoint. So on ray Cd, point C is the endpoint and d is a point on the line coming from the endpoint. On ray Dc, D is the endpoint.
10!
10/3
10 over 3 <3 Angel
dc = 73.91261929 feet. 72
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
8
10/3
20
if DC = 10 What is the measure of angle ABD?
The question cannot be answered since it is inconsistent. It first states that AB equals 5 cm and then AB equals 6 cm. Please check your typing and resubmit.
In order to answer that, we'd have to know the relationship between 'AB' and 'DC'. You've told us nothing about how they're connected. Could there be a picture that's supposed to go along with this question, maybe ?
value of $10 from 1928c green seal, washintong dc.