The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)
I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
the derivative of ln x = x'/x; the derivative of 1 is 0 so the answer is 500(1/x)+0 = 500/x
The derivative of tan(x) is sec2(x).(Which is the same as 1/cos2(x).
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The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x
The derivative of cos(x) is negative sin(x). Also, the derivative of sin(x) is cos(x).
The derivative with respect to 'x' of sin(pi x) ispi cos(pi x)
The derivative of csc(x) is -cot(x)csc(x).
The derivative of sec(x) is sec(x) tan(x).
The derivative of cot(x) is -csc2(x).
Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
derivative of sec2(x)=2tan(x)sec2(x)
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
Derivative of 1/x 1/x = x-1 Take the derivative (-1)x(-1-1) = -x-2 = 1/x2
the derivative of ln x = x'/x; the derivative of 1 is 0 so the answer is 500(1/x)+0 = 500/x