More precisely, I think you're asking whether the set of n X n matrices forms an abelian group under multiplication. The answer is no (assuming n>1). For example
(1 0)(0 1) = (0 1)
(0 0)(0 0) (0 0),
but
(0 1)(1 0) = (0 0)
(0 0)(0 0) (0 0). However, the set of n x n diagonalmatrices does form an Abelian set. This is true regardless of the direction of the diagonality, right-to-left or left-to-right. Note that the resulting matrix will also be diagonal, but always right-to-left.
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No. It is not even closed. sqrt(3)*sqrt(3) = 3 - which is rational.
No.
No. One of the group axioms is that each element must have an inverse element. This is not the case with integers. In other words, you can't solve an equation like: 5 times "n" = 1 in the set of integers.
A set is closed under multiplication if for any two elements, x and y, in the set, their product, x*y, is also a member of the set.
yes