(x + 2)(3x - 1)(3x + 1)
x2 - 9x + 20 = (x - 4)( x - 5)
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
x2 + 9x2 = 10x2
32 minus the product of 9 and a number is 140 the answer is 12. 32-9x=140 9x=108 x=12
x2-9x can be factored by taking x out of each term x(x-9)
(3x + 8)(3x - 8)
(9x + 8)(9x - 8)
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
(x + 3)(3x - 2)
x2-9x+8=0 has two solutions:x = 8x = 1
(x + 12)(x - 3)
9x2-9x-10 = (3x+2)(3x-5) when factored
(x + 2)(3x - 1)(3x + 1)
9x2 - 18x + 99(x2 - 2x + 1)==========
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
9x squared plus 16 = 0 factored is plus and minus 4/3 i.