To solve X^3 x X^4, you add the exponents since you are multiplying like bases. This results in X^(3+4) = X^7. So, X^3 x X^4 = X^7.
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Well, honey, when you're multiplying those bad boys X3 and X4, you just add the exponents because they have the same base X. So, X3 x X4 is the same as X(3+4), which simplifies to X7. Easy peasy lemon squeezy!
Oh, dude, solving X3 x X4 is like, super easy. You just add the exponents together, so X3 x X4 is X7. It's like combining powers, you know? Math can be fun when you don't overthink it.
∫x3ex4 dx = 1/4ex4 + c To solve, let y = x4, then: dy = 4x3 dx ⇒ 1/4dy = x3 dx ⇒ ∫x3ex4 dx =∫ex4 x3 dx = ∫ey 1/4 dy = 1/4ey + c but y = x4, thus: = 1/4ex4 + c
For example, (x3)(x4) = (x3+4) = x7 Also, (x5)2 = x(5)(2) = x10
x2 • (5x2 + x + 8)
To find p(x) / q(x), we first need to substitute the expressions for p(x) and q(x) into the formula. So, p(x) = 20x^5 - 20x^4 + 24x^2 and q(x) = 4x^2. Therefore, p(x) / q(x) = (20x^5 - 20x^4 + 24x^2) / 4x^2. Simplifying this expression, we get 5x^3 - 5x^2 + 6.
The answer is (no.) x3 = (no. 2) - 1 = (no. 3) x3= (no.4) x4 and so on... 1 x 3 = 3 - 1 = 2 x 3 = 6 - 1 = 5 x 3 = 15 - 1 = 14 x 3 = 42 - 1 = 41. :D Hope i helped