you can find the rest of the numbers in the sequence by using inductive reasoning or noticing a pattern 26 , 17 , 8 , -1 , -10 it appears that you are subracting 9 each time. 26-9=17 17-9=8 8-9=-1 (8-9 changes to 8+-9 if you need to see that step) -1-9=-10 (-1-10 changes to -1+-9 if you need to see that)
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
10n + 1
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
7
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
10n + 1
7
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
6n+10
7n - 4
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
15(1)
By "the nth term" of a sequence we mean an expression that will allow us to calculate the term that is in the nth position of the sequence. For example consider the sequence 2, 4, 6, 8, 10,... The pattern is easy to see. # The first term is two. # The second term is two times two. # The third term is two times three. # The fourth term is two times four. # The tenth term is two times ten. # the nineteenth term is two times nineteen. # The nth term is two times n. In this sequence the nth term is 2n.
no clue
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).