8.25
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
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If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
Using the distance formula the length of ab is 5 units
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
(0,8)2 + (0,2)2 8(2=69 2(2=4 69+4=74√
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8
The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.It gets a lot more complicated in the latter case if they can be non-integers.
We can't see the drawing, so we don't know how QX is related to AB. Maybethat's the whole problem. Perhaps you ought to look at the drawing.
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).