I’m just challenging you, and you’re not so smart because this question is sooo easy and you want me to solve it myself!
why dont you use a calculator
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.
The equation (b2 - 2b) + (3b - 6) = b2 + b - 6
in it's simplest form square root everything to get: a+b=8 i.e. a=8-b or b=8-a
b2 - 7b - 6b = -4(-4)2 - 7(-4) - 6 = 16 +28 - 6 = 38
30
A squared = 6x6 = 36 B squared = 8x8 = 64 Square root of 36+64 = 10 Given: a2 + b2 = c2 a = 6 and b = 8. We need to find the value of c. a = 6 implies a2 = 62 = (6*6) = 36. b = 8 implies b2 = 82 = (8*8) = 64. a2 + b2 = c2 implies 62 + 82 = c2 c2 = 36 + 64 c2 = 100 c2 = 102 c = 10
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.
The equation (b2 - 2b) + (3b - 6) = b2 + b - 6
6
b3 - 5b2 + 12 = (b - 2)(b2 - 3b - 6)Check:(b - 2)(b2 - 3b - 6)= b(b2 - 3b - 6) - 2(b2 - 3b - 6)= b3 - 3b2 - 6b - 2b2 + 6b + 12= b3 - 5b2 + 12
b(b - 8)
A = 1/2 BH A = 24 = 1/2 BH 24 * 2 = BH 48 = BH H = B - 2 48 = B(B - 2) B2 - 2B = 48 B2 - 2B - 48 = 0 (B - 8)(B + 6) = 0 B = 8 or -6 Since the base cannot be negative, the base is 8 and the height is 6 (8 - 2)
b
A2 + B2 = C2 If C=8, then A2 + B2 = 64
(b + 8)(b + 4)
in it's simplest form square root everything to get: a+b=8 i.e. a=8-b or b=8-a
-8 -6(-8) = 48