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Is the equation for a circle a function?
The equation for a circle is a function in that it can be graphed and charted. One common equation is x^2 + y^2 = r^2.
The center of a circle is located at c(3-13). The x-axis is tangent to the circle at (30). Find the equation of the circle?
Equation of the circle: (x-3)^2 +( y+13)^2 = 169
What is the equation of a circle that passes through the points of 5 5 and 8 5 and 5 1 on the Cartesian plane showing work?
The points will form a right angle triangle in a circle whose hypotenuse is its diameterLength from (8, 5) to (5, 1) = 5Midpoint: (6.5, 3) which is the centre of the circleRadius: 2.5Equation of the circle: (x-6.5)^2+(y-3)^2 = 6.25
I have a maths question i dont get please help me!"Describe fully the graph which has the equation x² + y² = 16."?
It's a circle. The equation of a circle is x^2+y^2=r^2. So the equation you've given is a circle with a radius of 4 and, since there are no modifications to the x or y values, the center of the circle is located at (0,0).
Find an equation of the circle that has center 0 2 and passes through the origin.?
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4
Which is the standard equation for a circle centered at origin with raduis r?
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
When you make the circle bigger or smaller which number of the standard equation for a circle centered at the orgin changes?
In the standard equation of a circle centered at the origin, (x^2 + y^2 = r^2), the number that changes when you make the circle bigger or smaller is (r^2), where (r) is the radius of the circle. As you increase or decrease the radius, (r^2) will correspondingly increase or decrease. The values of (x) and (y) remain constant as they represent points on the circle.
Which is the standard equation for a circle centered at the origin with the radius r?
The standard equation for a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this equation, ( (x, y) ) represents any point on the circle, and ( r ) is the distance from the center to any point on the perimeter. This equation describes all points that are exactly ( r ) units away from the origin (0, 0).
What is the standard form of the equation of a circle with its center at (2 -3) and passing through the point (-2 0)?
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
When you make the circle smaller which number in the standard equation for a circle centered at the origin decreases?
The radius of the circle decreases when you make the circle smaller.
How do you draw a flow chart to find the equation of a circle passing through three given points?
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
What is the equation of the points (31) and has a radius length of 2?
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
How To find the standard equation for a circle centered at the origin we use the distance formula since the radius measures?
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
What is the equation of a circle whose diameter end points are at 8 7 and 2 -3 on the Cartesian plane?
End points: (8, 7) and (2, -3) Midpoint: (5, 2) which is the center of the circle Radius: square root of 34 Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the equation of the points (-12) and has a radius of length 3?
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
