Two points do not provide enough information to define a circle: a minimum of three points is required to uniquely define a circle unless one of the points happens to be the centre and the other is on the circle. In that case, however, it is necessary to know which is which.
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The equation for a circle is a function in that it can be graphed and charted. One common equation is x^2 + y^2 = r^2.
Equation of the circle: (x-3)^2 +( y+13)^2 = 169
The points will form a right angle triangle in a circle whose hypotenuse is its diameterLength from (8, 5) to (5, 1) = 5Midpoint: (6.5, 3) which is the centre of the circleRadius: 2.5Equation of the circle: (x-6.5)^2+(y-3)^2 = 6.25
It's a circle. The equation of a circle is x^2+y^2=r^2. So the equation you've given is a circle with a radius of 4 and, since there are no modifications to the x or y values, the center of the circle is located at (0,0).
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4