(1,head,head),(1,head,tail),(1,tail,head),(1,tail,tail)
(2,head,head), (2,head,tail),(2,tail,head),(2,tail,tail),
(3,head,head), (3,head,tail),(3,tail,head),(3,tail,tail),
(4,head,head), (4,head,tail),(4,tail,head),(4,tail,tail),
(5,head,head), (5,head,tail),(5,tail,head),(5,tail,tail),
(6,head,head), (6,head,tail),(6,tail,head),(6,tail,tail),
Two times the number of outcomes of the spin - which is not specified in the question.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
The possible outcomes of a coin that is flipped are heads or tails.
When flipping a coin, there are two possible outcomes: heads (H) or tails (T). If you flip one coin, there are 2 outcomes. If you flip multiple coins, the total number of outcomes is calculated as (2^n), where (n) is the number of coins flipped. For example, flipping 3 coins results in (2^3 = 8) possible outcomes.
when you toss a coin three times, the total number of possible outcomes is
eight
The cube has 6 possible outcomes.The coin has 2 possible outcomes.There are 6 x 2 = 12 possible outcomes for a trialthat involves both the cube and the coin.
For one spin of a fair spinner (assuming it has a certain number of equally spaced sections, such as 4) and one toss of a coin, the total number of outcomes can be calculated by multiplying the number of outcomes for each event. If the spinner has 4 sections, there are 4 outcomes from the spin and 2 outcomes from the coin toss (heads or tails). Therefore, the total number of outcomes is 4 (from the spinner) multiplied by 2 (from the coin), resulting in 8 possible outcomes.
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
There are 6*6*2 = 72 possible outcomes.
Two times the number of outcomes of the spin - which is not specified in the question.
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
There are 25 = 32 possible outcomes.
There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8.