If: x = 2y-2 and x^2 = y^2+7
Then: (2y-2)^2 = y^2+7 => 4y^2-8y+4 = y^2+7 => 3y^2-8y-3= 0
Solving the above quadratic equation: y = -1/3 or y = 3
Solutions by substitution: when y=-1/3 then x=-8/3 and when y=3 then x=4
The solutions are: x = 4, y = 2 and x = -4, y = -2
They are: (3, 1) and (-11/5, -8/5)
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
Four.
The solutions are: x = 4, y = 2 and x = -4, y = -2
They are: (3, 1) and (-11/5, -8/5)
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
Four.
4
Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1
If: x = 2y-2 and x^2 = y^2+7 Then: (2y-2)^2 = y^2+7 So: (2y-2)(2y-2) = y^2+7 It follows: 4y^2-y^2-8y+4-7 = 0 => 3y^2-8y-3 = 0 Solving the above quadratic equation: y = -1/3 or y = 3 Solutions: when y = 3 then x = 4 and when y = -1/3 then x = -8/3
If you mean: x2+2x+1 = 0 then it is a quadratiic equations whose solutions are equal because x = -1 and x = -1
True. Both equations can be factored to x(x+4)=0 and 3x(x+4)=0, respectively. Therefore, the solutions for both equations are x=0 and x=-4. So, yes, the solutions are identical because math doesn't play favorites.