0
Natural numbers only:
Sequence length 1: 48.
Sequence length 3: 15, 16, 17.
If you allow for negative numbers, the following two are also possible:
Sequence length 33: -14, -13, ... , 0, 1, ..., 15, 16, 17.
Sequence length 97: -47, -46, ..., 47, 48.
There is no other sequence with a total of 48 in the whole number domain.
A solution would be:
Let m be the first consecutive number. Hence:
m + 1 = Second consecutive no.
m + 2 = Third consecutive no.
So the equation will be:
1st no. + 2nd no. + 3rd no = 48
m + (m + 1) + (m + 2) = 48
3m + 3 = 48
3m = 48 - 3
3m = 45
Dividing both sides by 3 gives:
m = 15
by substitution:
15 + 1 = Second consecutive no. = 16
15 + 2 = Third consecutive no. = 17
Hence, the numbers are 15, 16 and 17. :-)
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What is the sum of two consecutive whole numbers of 97?
The numbers are 48 and 49.
The sum of three consecutive numbers is 30 what are the numbers?
nine, ten and eleven. Three consecutive numbers that total thirty
The sum of three consecutive even numbers is 48 what are the smallest of these numbers?
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
Three consecutive numbers that add up to a multiple of three?
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
The sum of 2 consecutive whole numbers is 97 what are the 2 numbers?
Okay, so two consecutive numbers are basically (n) and (n + 1).now:97 = n + (n+1)97 = 2n + 1- 1 -196 = 2n/2 /2n = 96/2n = 48We said that the first number is (n) and the second number is (n + 1), that means that the numbers are 48 and 49.
