Natural numbers only:
Sequence length 1: 48.
Sequence length 3: 15, 16, 17.
If you allow for negative numbers, the following two are also possible:
Sequence length 33: -14, -13, ... , 0, 1, ..., 15, 16, 17.
Sequence length 97: -47, -46, ..., 47, 48.
There is no other sequence with a total of 48 in the whole number domain.
A solution would be:
Let m be the first consecutive number. Hence:
m + 1 = Second consecutive no.
m + 2 = Third consecutive no.
So the equation will be:
1st no. + 2nd no. + 3rd no = 48
m + (m + 1) + (m + 2) = 48
3m + 3 = 48
3m = 48 - 3
3m = 45
Dividing both sides by 3 gives:
m = 15
by substitution:
15 + 1 = Second consecutive no. = 16
15 + 2 = Third consecutive no. = 17
Hence, the numbers are 15, 16 and 17. :-)
The numbers are 48 and 49.
The answer 2 this question is 47 and 48
nine, ten and eleven. Three consecutive numbers that total thirty
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
No whole 3 consecutive numbers total 46.
The numbers are 15, 16 and 17.
Any pair of consecutive numbers will have an odd total. 10 and 12 are consecutive even numbers that total 22.
The numbers are 48 and 49.
The smallest is 15.
There are no three consecutive numbers with a sum of 170.
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
48/3 = 16 so the three numbers are 15, 16, 17
The numbers are 47 and 48. (47 x 48 = 2,256)
It is not possible in our Universe that two consecutive numbers can total an even number, since any two consecutive numbers must be an odd and an even (or vice versa). There are two consecutive odd numbers which total 132 ie 65 and 67
The smallest is 14.
The numbers are 15, 16 and 17.