Natural numbers only:
Sequence length 1: 48.
Sequence length 3: 15, 16, 17.
If you allow for negative numbers, the following two are also possible:
Sequence length 33: -14, -13, ... , 0, 1, ..., 15, 16, 17.
Sequence length 97: -47, -46, ..., 47, 48.
There is no other sequence with a total of 48 in the whole number domain.
A solution would be:
Let m be the first consecutive number. Hence:
m + 1 = Second consecutive no.
m + 2 = Third consecutive no.
So the equation will be:
1st no. + 2nd no. + 3rd no = 48
m + (m + 1) + (m + 2) = 48
3m + 3 = 48
3m = 48 - 3
3m = 45
Dividing both sides by 3 gives:
m = 15
by substitution:
15 + 1 = Second consecutive no. = 16
15 + 2 = Third consecutive no. = 17
Hence, the numbers are 15, 16 and 17. :-)
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The numbers are 48 and 49.
nine, ten and eleven. Three consecutive numbers that total thirty
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
Okay, so two consecutive numbers are basically (n) and (n + 1).now:97 = n + (n+1)97 = 2n + 1- 1 -196 = 2n/2 /2n = 96/2n = 48We said that the first number is (n) and the second number is (n + 1), that means that the numbers are 48 and 49.