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What is the function for this function table x -3 -2 0 1 2 y 9 4 0 1 4?
Y = x2
What is the trigonometric function sec?
The function sec(x) is the secant function. It is related to the other functions by the expression 1/cos(x). It is not the inverse cosine or arccosine, it is one over the cosine function. Ex. cos(pi/4)= sqrt(2)/2 therefore secant is sec(pi/4)= 1/sqrt(2)/2 or 2/sqrt(2).
Is the sequence 2 4 8 16 32 a linear function?
No.
What are the inputs of the following function -3 2 -4 2 8 3 7 1?
{(-3, 2), (-4, 2), (8, 3), (7, 1)}
How do you find zeros of a function in intercept form?
if you want to find the zero/null /x-intercept of any given function you have to find the x that makes it zero. therefore if f(x) = 2x +4 you have to put f(x) = 0 0 = 2x +4 2x = -4 x=-2 if you subsitute -2 for x you will find that the function f(x) will equal zero f(x)= 2 * (-2) +4 f(x) = -4 +4 f(x) = 0 if you have more complex functions like squared your approach will look something like this say g(x) is a function of x² g(x)=(x-2)² +4 set g(x)= 0 0= (x-2)² -4 4= (x-2) ² + or - radical (4) = x -2 2 + radical (4) = x or 2 -radical (4) = x x=4 or x = 0 remember radicals always have two solutions
What is another name for the root of a function?
The "root" of a function is also called the "zero" of a function. This is where the function equals zero. The function y=4-x2 has roots at x=2 and x=-2 The function y=4-x2 has zeroes at x=2 and x=-2 Those are equivalent statements.
What is the function for this function table x -3 -2 0 1 2 y 9 4 0 1 4?
Y = x2
What is the domain of the function f x x 2 plus 4?
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
What is the lower bound of the function x4 - 2?
You obtain the absolute minimum of the function when x=0. (0^4)-2 =0-2=-2. So, the lower bound of the function is -2.
How do you find zeros on each function?
Set the equation equal to zero. For example, take the function F(x) = x^2 - 4 Find the zeroes by x^2 - 4 = 0 x^2 = 4 sqrt(x^2) = sqrt(4) x = +/- 2
What would the equation of a line be if it went through the point 2 comma 2 and its yintercept was 10?
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
What is the trigonometric function sec?
The function sec(x) is the secant function. It is related to the other functions by the expression 1/cos(x). It is not the inverse cosine or arccosine, it is one over the cosine function. Ex. cos(pi/4)= sqrt(2)/2 therefore secant is sec(pi/4)= 1/sqrt(2)/2 or 2/sqrt(2).
How do you find the range of the function with the given domain?
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
Write a set of coordinates that describes a function?
{(5, 2), (3, 4), (1, 2), (−1, 4)}
Which of the ordered pairs below could NOT be in this function{(0, 0), (1, 1), (2, 2), (4, 3)}?
(2, 4)
Does y equals x plus 4 rpresent a function?
Yes it does, Remember Y values are generally function values. So, putting a value into this function, substitution a integer for X, fives you the Y value. Y = X + 4 ( make X 2 ) Y = (2) + 4 Y = So, when X = 2, Y = 6. The function.
Which is a zero function x2 plus 6x plus 8?
(x + 2)(x + 4) x = -2, -4
