2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
x = -8, y = 10
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
5y+8=7y 2y=8 y=4
10x + 2y + 8z - 5x + 4z - 4y = 10x - 5x + 2y - 4y + 8z + 4z = (10 - 5)x + (2 - 4)y + (8 + 4)z = 5x - 2y + 12z
-2y=x+8 is the answer
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
Sum Numb!
(3, 5)
(3, 2)
(-2, 4)
Both of them are equations!The solution is (x, y) = (2, 1).
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
3x + 2y = 8 This is an equation. It could be the equation of a line.
x = 2y = 4
8 + 2y = 6 Subtract 8 from both sides: 2y = -2 Divide both sides by 2: y = -1