Isn't it the sum of all sides? 8m+8m+3m+3m = 22m
if you meant: (-3)x²-5x+1=8x²-2x-9x=(±√(449)-3)/22 ≈ -0.1363636363636 ± 1.9263291000379x1=(√(449)-3)/22 ≈ 0.8268009136553x2=(-√(449)-3)/22 ≈ -1.0995281863826
Are you asking how to solve for x if those two expressions equal each other? -3x2 - 5x + 1 = 8x2 - 2x - 9 11x2 + 3x - 10 = 0 11x2 + 3x = 10 x2 + 3x/11 = 10/11 x2 + 3x/11 + (3/22)2 = 10/11 + (3/22)2 (x + 3/22)2 = 440/484 + 9/484 x + 3/22 = ± √(449 / 484) x = 3/22 ± √449 / 22 x = (3 ± √449) / 22 Are you asking to find the derivatives of each expression? if f(x) = -3x2 - 5x + 1 f'(x) = -6x - 5 if f(x) = 8x2 - 2x - 9 f'(x) = 16x - 2 Are you looking for their indefinite integrals? ∫(-3x2 - 5x + 1)dx = -x3 - 5x2/2 + x + C ∫(8x2 - 2x - 9)dx = 8x3/3 - x2 - 9x + C
-3x2 + 16x + 12 = -3x2 + 18x - 2x + 12 = -3x*(x - 6) - 2(x - 6) = -(3x + 2)*(x - 6)
No.
10x3 + 3x2
8x2 + 16x + 8 = 0
3x2 + 27x +60
8x2 + 15 + 26x = 8x2 + 26x + 15 = 8x2 + 20x + 6x + 15 = 4x(2x + 5) + 3(2x + 5) = (2x + 5)(4x + 3)
What is the result of adding -3x²-5x +1 and 8x²-2x-9?
7Improved Answer:8x2-18x+9 = (4x-3)(2x-3)
8x2+6x-35 = (2x+5)(4x-7) when factored
3x2=6+38=44
3x2+26x+16 When factorised: (3x+2)(x+8)
3x2 + 10x + 3 = (x + 3)(3x + 1).
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
Isn't it the sum of all sides? 8m+8m+3m+3m = 22m