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11x(2x - 1) = 0 so either 11x = 0 or x = ½
Their sum is 4.
3x2 - 7x = -2 3x2 - 7x + 2 = 0 3x2 - 6x - x + 2 = 0 3x(x - 2) - 1(x - 2) = 0 (x - 2)(3x - 1) = 0 so x - 2 = 0 or 3x - 1 = 0 so x = 2 or x = 1/3
3x^0 = 3(x^0) = 3 (3x)^0 = 1
6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
3x squared - 12x - 24 = 0, and -b/a = sum of the roots, and c/a = product of the roots
Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
(3x-4)(x+5)
If you mean: 3x squared -11x -20 = 0 Then: x = -5 or x = 4/3
20X - 3 + 3X = 11X + 5 - 8 put those like terms together on the left 23X - 3 = 11X + 5 - 8 like terms together on the right 23X - 3 = 11X - 3 this equation admits of no solution, so is not true X would = 0
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
11x(2x - 1) = 0 so either 11x = 0 or x = ½
- x - 2y + 9x - y + 3x = 0 1.) Add like - terms 11x - 3y = 0 x = - 3/11y y = 11/3y
Their sum is 4.
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.