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3w- plus 2 equals 2w plus 3?
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5
What is 5-32 plus 2w equals -7?
Using basic algebra we can solve this problem. First we need to write out the problem:5-32+2w = -7-27+2w = -72w = 20w = 10
The lenght of a rectangle is 3 inches less than twice the width if the perimeter of the rectangel is 18 inches find the width of the rectangel?
In this rectangle we'll call the length L and the width W We know that L + 3 = 2W So, if we subtract 3 from each side we get L = 2W - 3 We also know that 2L + 2W = 18 Now we can substitute the L terms 2(2W - 3) + 2W = 18 4W - 6 + 2W = 18 4W + 2W = 18 + 6 6W = 24 W = 4 So, if L + 3 = 2W then L + 3 = 8.... therefore L = 5 So now, we'll check that the measurements we've ended up with work out... 2L + 2W = 18 5 + 5 + 4 + 4 does indeed = 18
If you know both the perimeter an the length of a rectangle how can you determine the width of the rectangle?
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
What are the dimensions of a rectangle with the area of 27 yds sq. and the length is 3 yds less than twice the width?
Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
What is the width of a rectangle if it has a length of 10cm and a perimeter of 34cm?
p=2l+2w 34= 2(10) +2w 34= 20 +2w 14= 2w w=7
What is 3n-2w and how do you work it out?
3n-2w and how do you work it out = 1
What is w if 2w equals 16?
what is w if 2w = 16
The perimeter of a rectangular painting is 350 centimeters If the length of the painting is 93 centimeters what is its width?
Perimeter = 2L + 2W 350 = 2(93) + 2W 350 = 186 + 2W 350 - 186 = 186 - 186 + 2W 164 = 2W 164/2 = 2W/2 82 = W So the width is 82 cm.
The length of a garden is 2 times the width The perimeter of the graden is 144ft Write and solve an equation to find the length and the width of the garden?
length = 48, width = 24 l = 2w 2l + 2w = 144 2l + 2w = 144 2(2w) + 2w = 144 4w + 2w =144 w = 144/6 w = 24 l = 2w l = 2(24) l = 48
The distance around a rectangle is 24 inches the length is twice as long as the width what is the measure of one width?
Circumference of rectangle (C) = 2w+2l l=2w C=2w+2(2w) =2w+4w=6w=24 w=24/6=4"
3w- plus 2 equals 2w plus 3?
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5
What eqations represents the formula for perimiter of a rectangle p equals 2l plus 2w solve for l?
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
The perimeter of a floor is 24 meters the length is twice that of the breadth find 1 the length and 2 the breadth?
2l+2w=24 l=2w 2(2w)+2w=24 4w+2w=24 6w=24 w=4 l=2w=2*4=8 Length is 8 meters, the width (or breadth) is 4 meters.
What is the answer to this algebra 1 problem -36 plus 2w equals -8w plus w?
-36 + 2w = -8w + w -36 + 2w = -7w -36 = -7w - 2w -36 = -9w w = -36/-9 = 4
5w plus 2 equals 2w plus 5?
5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1
What is a number that is multiplied by the variable in an algerbraic expreesion?
Well, it really depends on the problem. A variable can be multiplied by just about any number.
