84.42 or 42.21
Power 2: units digit 9. Multiply by 49 again to get power 4: units digit 1. So every 4th power gives units digit 1. So 16th power has units digit 1, so the previous power, the 15th must have units digit 3.
The digit in the units column of the number 7157 is 7.
the unit digit is the last digit from left or ones digit
There is no simple formula for that; I suggest you look up the prime numbers in a table of prime numbers, analyzing each prime number in the range 10-99 whether it fulfills this specific criterion.
The prime numbers with a units digit of 1 in the range 1 - 121 are :- 11, 31, 41, 61, 71 and 101.......making 6 primes in total.
They are: 3 13 23 43 53 73 and 83 which as a fraction is 7/25 because there are 25 primes between one and a hundred
The units digit of a whole number is always the rightmost digit.
42.21 or 84.42
84.42 or 42.21
Power 2: units digit 9. Multiply by 49 again to get power 4: units digit 1. So every 4th power gives units digit 1. So 16th power has units digit 1, so the previous power, the 15th must have units digit 3.
The digit in the units column of the number 7157 is 7.
The units digit of 159*445*7762*39 is the units digit of the product of the units digits of the four numbers, that is, the units digit of 9*5*2*9 Since there is a 5 and a 2 in that, the units digit is 0.
Oh, dude, okay, so when you raise 2013 to the power of 2013, you're basically asking what the units digit of that massive number is. Well, lucky for you, you don't need to calculate the whole thing because the units digit of a number repeats in a pattern. So, the units digit of 2013 to the power of 2013 is 7. Cool, right?
The number in the units digit of the number 921 is 9.
the unit digit is the last digit from left or ones digit
There is no simple formula for that; I suggest you look up the prime numbers in a table of prime numbers, analyzing each prime number in the range 10-99 whether it fulfills this specific criterion.