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What is the distance between the points 3 and -4 and 3 and -8 and 1?
Distance formula: square root of (x1-x2)2+(y1-y2)2
What is the distance between the points 4 7 and 7 8?
The Pythagorean distance is sqrt[(4 - 7)2 + (7 - 8)2] = sqrt[9 + 1] = sqrt(10) = 3.162 approx.
What is the distance between two points -3 7 and -6 4?
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points
What is the distance between points 0 4 and -4 6?
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============
What is the distance between the origin and (-3 -4)?
1
What is the distance between the points -1 -9 and 4 -2?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the points (-5 2) and (4 9)?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
What is the distance between points (-42)and (12)?
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between the points (24) and (-18)?
If you mean points of (2, 4) and (-1, 8) then the distance works as 5
What is the distance between the points -1 1 and 1 -1?
The distance between the points can be calculated by using the difference in the x coordinates, the difference in the y coordinates and Pythagoras. distance = sqrt((difference_in_x_coords)2 + difference_in_y_coords)2) So for the points (-1, 1) and (1, -1) the distance between them is: sqrt((-1 - 1)2 + (1 - -1)2) =sqrt(22 + 22) =sqrt(4 + 4) = sqrt(8) ~= 2.83
What is the distance between points (44) and (-2-2)?
Points: (4, 4) and (-2, -2) Distance: 6 times square root of 2
What is the the distance between the points (2 4) and (5 0)?
Points: (2, 4) and (5, 0) Distance: 5
What is the equation of a circle whose diameter end points are at 10 -4 and 2 2 on the Cartesian plane?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
Which expression gives the distance the points (1 -2) and (2 4)?
square root of (5-9)^2+(1+6)^2
What points' vertical distance from the origin is twice their horizontal distance?
The points where the vertical distance from the origin is twice the horizontal distance can be represented by the equation ( y = 2x ) and ( y = -2x ). This means for any point ((x, y)) on these lines, the absolute value of (y) is twice the absolute value of (x). Therefore, points such as ((1, 2)), ((2, 4)), ((-1, -2)), and ((-2, -4)) satisfy this condition.
