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It is sqrt(62 + 32) = sqrt(36 + 9) = sqrt(45) = 3*sqrt(5) = 6.7082 (approx).
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What is the distance between the points 3 and -4 and 3 and -8 and 1?
Distance formula: square root of (x1-x2)2+(y1-y2)2
What is the distance between the points 4 7 and 7 8?
The Pythagorean distance is sqrt[(4 - 7)2 + (7 - 8)2] = sqrt[9 + 1] = sqrt(10) = 3.162 approx.
What is the distance between two points -3 7 and -6 4?
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points
What is the distance between points 0 4 and -4 6?
(0, 4) and (- 4, 6) ???Distance = sqrt[(Y2 - Y1)2 + (X2 - X1 )2]Distance = sqrt[(6 - 4)2 + (- 4 - 0)2]Distance = sqrt( 4 + 16)Distance = sqrt(20)==============
What is the distance between the origin and (-3 -4)?
1
What is the distance between the points -1 -9 and 4 -2?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the points (-5 2) and (4 9)?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
What is the distance between points (-42)and (12)?
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
What is the distance between the points (24) and (-18)?
If you mean points of (2, 4) and (-1, 8) then the distance works as 5
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between the points -1 1 and 1 -1?
The distance between the points can be calculated by using the difference in the x coordinates, the difference in the y coordinates and Pythagoras. distance = sqrt((difference_in_x_coords)2 + difference_in_y_coords)2) So for the points (-1, 1) and (1, -1) the distance between them is: sqrt((-1 - 1)2 + (1 - -1)2) =sqrt(22 + 22) =sqrt(4 + 4) = sqrt(8) ~= 2.83
What is the the distance between the points (2 4) and (5 0)?
Points: (2, 4) and (5, 0) Distance: 5
What is the distance between points (44) and (-2-2)?
Points: (4, 4) and (-2, -2) Distance: 6 times square root of 2
What is the distance between the two points graphed below?
(-1, -3) (2, 4)
What is the equation of a circle whose diameter end points are at 10 -4 and 2 2 on the Cartesian plane?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
Which expression gives the distance the points (1 -2) and (2 4)?
square root of (5-9)^2+(1+6)^2
