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Obviously, both terms have the common factor "n". You get the other factor by dividing both terms by n. The result is "n + 2".
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What is 2n squared plus 5n plus 2?
That factors to (2n + 1)(n + 2)
How do you factor 2n2-15n plus 18?
(2n - 3)(n - 6)
What do you get when you factor 4n squared - 26n - 42?
are you sure you don't mean "4n squared - 26n + 42" ?? This would give 2(2n-7)(n-3) Davehx
What is the square of n squared plus 2n minus 1?
(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156
What is the value of n if 2n plus 7 equals 19?
2n plus 7 equals 19 2n equals 12 n equals 6
How would you factor 12n squared plus 4n cubed minus 7n?
n(2n - 1)(2n + 7)
What is 2n squared plus 5n plus 2?
That factors to (2n + 1)(n + 2)
What is 2n squared plus 4n?
If the given equation were factorized it would be: 2n2 + 4n = 2n(n+1) Another Answer:- The given expression when factored is 2n(n+2)
How do you factor 8n2 plus 36n plus 40?
4(n + 2)(2n + 5)
How do you factor 2n2-15n plus 18?
(2n - 3)(n - 6)
What is the answer for (two n minus three)(n squared plus 5 n minus 1)?
It is 2n^3 + 7n^2 - 13n + 3
What do you get when you factor 4n squared - 26n - 42?
are you sure you don't mean "4n squared - 26n + 42" ?? This would give 2(2n-7)(n-3) Davehx
What is the square of n squared plus 2n minus 1?
(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156
2n plus 5 n what is the value of n?
2n plus 5 n would be 7n and its impossible to solve the value of n.
What is 2n squared plus 6n mines 108?
If the question is, "What is the solution to 2n2 + 6n - 108 = 0 ?"The equation can be factored : 2n2 + 6n - 108 = (2n - 12)(n + 9) = 0If 2n -12 = 0 then n = 6If n + 9 = 0 then n = -9The roots of this equation are n = 6 and n = -9.
What is the value of n in the expession x cubed plus x squared minus 2nx plus n squared which has a remainder of 8 when divided by x minus 2?
n is 2. To solve, do the division: . . . . . . . . .x2 +. 3x + (6-2n) . . . -------------------------- x-2 | x3 + x2 - 2nx + n2 . . . . .x3 -2x2 . . . . .-------- . . . . . . . .3x2 - 2nx . . . . . . . .3x2 - . 6x . . . . . . . .---------- . . . . . . . . . (6-2n)x + n2 . . . . . . . . . (6-2n)x - 2(6-2n) . . . . . . . . . ---------------------- . . . . . . . . . . . . . . . .n2 + 2(6-2n) But this remainder is known to be 8, so: n2 + 2(6-2n) = 8 ⇒ n2 - 4n + 4 = 0 ⇒ (n - 2)2 = 0 ⇒ n = 2
What are the multiples of n 2?
If that's n squared, the multiples are n squared, 2 n squared, 3 n squared and so on. If that's n + 2, the multiples are n + 2, 2n + 4, 3n + 6 and so on.
