325 = 847288609443. The last digit is therefore "3".
On your calculator (if you have a scientific calculator; and if you don't but you are using Microsoft Windows you can get a scientific calculator up by going to Start and typing in "calc" in the run/search box) you will have a button that looks like this:
xy (i.e. x to the power of y)
If you type in "3" then press this button and then put in "25" and press equals you should get the above number!
It is 1.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
3
Power 2: units digit 9. Multiply by 49 again to get power 4: units digit 1. So every 4th power gives units digit 1. So 16th power has units digit 1, so the previous power, the 15th must have units digit 3.
A number is a multiple of 400 if the last 4 digits are a multiple of 400 The 1,000s digit is even and the last 3 digits are 000, 400 or 800 The 1,000s digit is odd and the last 3 digits are 200 or 600 It also works checking if the number is a multiple of 16 and 25 at the same time because 400 = 2⁴ x 5² = 16 x 25
To find the last digit of a number raised to a power, we can use the concept of modular arithmetic. The last digit of 333 to the power of 444 can be determined by finding the remainder when 333 is divided by 10, which is 3. Since the last digit of 333 is 3, we need to find the remainder of 444 divided by 4, which is 0. Therefore, the last digit of 333 to the power of 444 is the same as the last digit of 3 to the power of 4, which is 1.
1
It is 1.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
Well, isn't that a happy little math problem! When we look at the unit digit of powers of numbers, we focus on the cyclical pattern they follow. The unit digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then repeats. So, to find the unit digit of 3 to the power of 34 factorial, we look for the remainder when 34 factorial is divided by 4, which is 2. Therefore, the unit digit of 3 to the power of 34 factorial is 9.
To find the last digit of 373^333, we need to look for a pattern in the units digit of the powers of 3. The units digit of powers of 3 cycles every 4 powers: 3^1 = 3, 3^2 = 9, 3^3 = 7, 3^4 = 1, and then it repeats. Since 333 is one less than a multiple of 4, the units digit of 3^333 will be the third number in the cycle, which is 7. Therefore, the last digit of 373^333 is 7.
1155
3
3
it is 3
1
no