Any number that you choose can be the nth term. It is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question followed by your chosen number in the nth place. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
Having said that, the simplest rule that will fit these numbers indicates thatU(n) = -8*n + 5
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The nth term of the sequence is (n + 1)2 + 2.
2n +29
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
It is: 27-2n
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.