(n(n-1) divided by 2 + 1) multiplied by 3) +6
There is no pattern
12, 8
The sequence 6, 13, 20, 27 increases by 7 each time. This indicates it is an arithmetic sequence with a common difference of 7. The nth term can be expressed as ( a_n = 6 + 7(n-1) ), which simplifies to ( a_n = 7n - 1 ). Thus, the nth term is ( 7n - 1 ).
tn = 3n or 3*3* ... *3 (where there are n threes.)
after -9 it is -15 then -21, -27 and the ninth is -36
The nth term of the sequence is (n + 1)2 + 2.
5n+2
There is no pattern
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
2n +29
Willies
n3
12, 8
3^n These are powers of 3
the anser is that you are stupid
9 3 1