(n(n-1) divided by 2 + 1) multiplied by 3) +6
Wiki User
∙ 11y agoThere is no pattern
12, 8
tn = 3n or 3*3* ... *3 (where there are n threes.)
after -9 it is -15 then -21, -27 and the ninth is -36
If by using the formula: nth term = n2+2 the sequence is 3 6 11 18 27 38 51 66.Then it follows that by using the same formula the sequence is III VI XI XVIII XXVII XXXVIII LI LXVI in Roman numerals.
The nth term of the sequence is (n + 1)2 + 2.
The nth term is: n^2 +2 and so the next number will be 38
5n+2
There is no pattern
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
n3
Willies
2n +29
12, 8
3^n These are powers of 3
the anser is that you are stupid