Well, isn't that just a happy little sequence we have here! To find the pattern, we can see that the differences between the terms are increasing by 2 each time. So, the nth term can be found by the formula n^2 + 4. Just like painting a beautiful landscape, sometimes all we need is a little patience and observation to uncover the hidden beauty within numbers.
The nth term is 7n-4 and so the next number in the sequence is 31
Type your answer here... The next numbers in the sequence are 55, 70, 87, 106, 127, etc.
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5
2n^2-1
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) Γ 20 Therefore, the nth term is 11 + (n - 1) Γ 20, where n is the position of the term in the sequence.
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term is 7n-4 and so the next number in the sequence is 31
Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
Type your answer here... The next numbers in the sequence are 55, 70, 87, 106, 127, etc.
As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
5 to 7 is 27 to 17 is 1017 to 19 is 219 to 29 is 1029 to 31 is 2there fore following the pattern the nth term is 4131 to 41 is 10
Difference is 5,7,9,11,13 Second difference is 2 (2x)^2 gives 4,9,16,25 Difference between 2x^2 and sequence is -5 Thus, the nth term will be (2n)^2-5
2n^2-1
Oh, dude, it's like you're throwing numbers at me and expecting a magic trick. But hey, I'll humor you. The nth term for this sequence is n*8 + 7. So, if you want the 5th term, just plug in n=5 and voilΓ , you get 47. Math can be fun, right?
You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4