If the die is numbered 1,2,3,4,5,6, then the numbers you could roll on that time include:
Odd Numbers: 1,3,5
Greater than 3: 4,5,6
Apparently, every number appears but 2, so there is a 1/6 chance of NOT getting the favorable outcome.
The favorable outcome is the chance of prevailing in the event's request,
and in this case, has a 5/6 chance of taking place.
So.. the probability is 5/6 of a chance,
83.333%,
or .83 of a chance, repeating 3.
7
It is approx 0.99989, that is, a near certainty.
If they are normal dice, the probability is 0.
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
1 out of 6
The probability is 1/6.
The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.The probability that the number rolled, on a fair, six sided die, will be greater than 4 is 1/3.
It is 1/2 if it is a fair number cube which is rolled once.
1/2
If it is a fair die that is rolled once, then the probability is 2/3.
it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
The probability is 1/36.
1/6 = 16.67%
5/6 = 83.3%
4/12
It is: 1/6 Since a die is cubic in shape and has 6 sides, and there is an equal probability of getting any one of them facing up (assuming the die is not loaded), and there is only one number on a die greater than 5, that being 6, the probability of rolling such a number is therefore 1 in 6, or .1666...