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Find the vertex of y equals 3x2-4x equals 3?
y=3x^2-4x=3 y=3x^2-4x-3 y = ax^2 + bx + c is the parabola y = 3x^2-4x-3 x-coordinate of vertex is -b/2a = -(-4) / (2)(3) = +4 / (2)(3) = 4/6=2/3 y coordinate of the vertex: y = ax^2+bx+c y = 3(2/3)^2-4(2/3)-3 y= 3(4/9) -8/3 -3 y=12/9-8/3-3 = -13/3 Vertex : ( 2/3, , -13/3 )
Y2 - 4 over y plus 3 equals 2 - y - 2 over y plus 3?
(2y-4)/(y+3)=(2-y-2)/(y+3) --> multiply both sides by (y+3) 2y-4=2-y-2 --> 2-2=0 (right hand side) 2y-4=-y --> add y to both sides 3y-4=0 --> add 4 to both sides 3y=4 --> divide both sides by 3 y=4/3
What point is the intersection of the graphs of the lines 2X-Y equals 3 and X plus Y equals 3?
2X-Y=3 X+Y=3 ---------- 3X = 6 X=2 2(2)-Y=3 4-Y=3 Y=1 Point of interesection: (2,1).
What is the y intercept and slope of y 3 over 2 x?
There is a missing equals. When the equation of a line is written in the form: y = mx + c m is the gradient/slope of the line; and c is the y intercept. If your line is ``y = 3/2 x'' then y = 3/2 x → y = 3/2 x + 0 → slope is 3/2 & y intercept is 0.
What is (x3 - y3) divided by (x - y)?
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