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What is the point slope equation if the slope is 2?
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)
What is the equation of the line that passes through the point 1 -1 and has a slope of -3?
A line through point (X, Y) with slope m has equation: y - Y = m(x - X) → line through (1, -1) with slope -3 has equation: y - -1 = -3(x - 1) → y + 1 = -3x + 3 → y + 3x = 2
Which point lies on the line with point slope equation y - 2 5 (x-6)?
(6,2)
When does the line y equals x plus 2 cross the y axis?
If the equation of the line is written in the standard form: y = mx + c, then it crosses the y-axis at the point (0,c). Here y = x+2 so the y-intercept is (0,2).
Which of the following equations of a line is in point-slope form?
y -1 = -1/2( x -2 )
Where does the graph cross the y axis at in y equals 5x-2?
y = 5x - 2 This follows the general equation for a straight line y = mx + c. Where 'm' is the slope/gradient and 'c' is the y-intercept. At the point the line crosses the y-axis , then x = 0 Hence y = 5(0) - 2 y = -2 is the point the line intercept the y-axis.
Write the equation of a line perpendicular to the line y x - 3 and containing the point 8 -2?
y = -x + 6
Which of these is the point-slope equation of the line shown?
y+ 4= -2( x-2 )
Which line of reflection maps point K at (-2 2) to point K' at (2 -2)?
y=x
Which point lies on the line with point-slope equation y - 2 5(x - 6)?
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
Which point lies on the line with point slope equation y - 2 5(x-6)?
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
The point at which the line crosses the x-axis?
The point where the line crosses the x axis? Answer: the x -intercept The point where the line crosses the y axis? Answer: the y- intercept
Why does every line have at least one bisection point?
Every line segment has exactly one bisection point - not "at least one".A line segment has a length that is a finite real number, x, of some measurement units. Every real number can be divided by 2 to give another real number, y. Therefore y = x/2 or x = 2y.A point that is y units from one end of the line will also be x - y = 2y - y = y units from the other end. That is the point is the bisection point.
How do you write the point-slope form of the equation of the line?
y-y1=m(x-x1) m is the slope x1 is x of the given point y1 is y of the given point y stays as y x stays as x ex: P(1,2) m=2 y-2=2(x-1)
What is the point slope equation if the slope is 2?
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)
What is the equation of the line that passes through the point 1 -1 and has a slope of -3?
A line through point (X, Y) with slope m has equation: y - Y = m(x - X) → line through (1, -1) with slope -3 has equation: y - -1 = -3(x - 1) → y + 1 = -3x + 3 → y + 3x = 2
How do you find another possible set of coordinates of a point that has a slope of 2?
If you know one point on a graph and you also know the slope of the graph, you can use the point-slope equation to create the y-intercept form of the line. Doing this will allow you to plug in values for x or y to get any point on the graph. For example, say that the slope of the line is 2 and a point on the line is (3,2). The point-slope form is y - y1 = m(x - x1). Plug in (3,2) and the slope to get y - 2 = 2(x - 3). That simplifies to y = 2x - 4. I want to see what y-value falls on the line at x = 5, so I plug that in. I get y = 6. That means that there is also the point (5,6) on the graph.
