0
What else can I help you with?
What is the point slope equation if the slope is 2?
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)
What is the equation of the line that passes through the point 1 -1 and has a slope of -3?
A line through point (X, Y) with slope m has equation: y - Y = m(x - X) → line through (1, -1) with slope -3 has equation: y - -1 = -3(x - 1) → y + 1 = -3x + 3 → y + 3x = 2
Which point lies on the line with point slope equation y - 2 5 (x-6)?
(6,2)
Which of the following equations of a line is in point-slope form?
y -1 = -1/2( x -2 )
When does the line y equals x plus 2 cross the y axis?
If the equation of the line is written in the standard form: y = mx + c, then it crosses the y-axis at the point (0,c). Here y = x+2 so the y-intercept is (0,2).
Write the equation of a line perpendicular to the line y x - 3 and containing the point 8 -2?
y = -x + 6
Where does the graph cross the y axis at in y equals 5x-2?
y = 5x - 2 This follows the general equation for a straight line y = mx + c. Where 'm' is the slope/gradient and 'c' is the y-intercept. At the point the line crosses the y-axis , then x = 0 Hence y = 5(0) - 2 y = -2 is the point the line intercept the y-axis.
Which line of reflection maps point K at (-2 2) to point K' at (2 -2)?
y=x
Which of these is the point-slope equation of the line shown?
y+ 4= -2( x-2 )
Which point lies on the line with point-slope equation y - 2 5(x - 6)?
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
Which point lies on the line with point slope equation y - 2 5(x-6)?
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
The point at which the line crosses the x-axis?
The point where the line crosses the x axis? Answer: the x -intercept The point where the line crosses the y axis? Answer: the y- intercept
How do you write the point-slope form of the equation of the line?
y-y1=m(x-x1) m is the slope x1 is x of the given point y1 is y of the given point y stays as y x stays as x ex: P(1,2) m=2 y-2=2(x-1)
Why does every line have at least one bisection point?
Every line segment has exactly one bisection point - not "at least one".A line segment has a length that is a finite real number, x, of some measurement units. Every real number can be divided by 2 to give another real number, y. Therefore y = x/2 or x = 2y.A point that is y units from one end of the line will also be x - y = 2y - y = y units from the other end. That is the point is the bisection point.
What is the point slope equation if the slope is 2?
If (p, q) is any point on the line, then the point slope equation is: (y - q)/(x - p) = 2 or (y - q) = 2*(x - p)
What is the equation of the line that passes through the point 1 -1 and has a slope of -3?
A line through point (X, Y) with slope m has equation: y - Y = m(x - X) → line through (1, -1) with slope -3 has equation: y - -1 = -3(x - 1) → y + 1 = -3x + 3 → y + 3x = 2
How do you find another possible set of coordinates of a point that has a slope of 2?
If you know one point on a graph and you also know the slope of the graph, you can use the point-slope equation to create the y-intercept form of the line. Doing this will allow you to plug in values for x or y to get any point on the graph. For example, say that the slope of the line is 2 and a point on the line is (3,2). The point-slope form is y - y1 = m(x - x1). Plug in (3,2) and the slope to get y - 2 = 2(x - 3). That simplifies to y = 2x - 4. I want to see what y-value falls on the line at x = 5, so I plug that in. I get y = 6. That means that there is also the point (5,6) on the graph.
