0
x^(3) + x^(2) + 4x + 4
Factirise
x^(2)(x + 1) + 4(x+1) =>
(X^(2) + 4)(x + 1) = >
(x^(2) + 2^(2))(x + 1)
NB ; REmember two squared terms with a positive (+) between then does NOT factor.
What else can I help you with?
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
What is x plus 4 divided by x3 -11x plus 20?
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
What is the quotient and remainder if any when the expession 4x4 -x3 plus 17x2 plus 11x plus 4 is divided by 4x plus 3?
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
What is the factor of X3 - 2x2 - 4x plus 8?
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
What is the factorization of this trinomial x3 - 10x2 plus 24x?
x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x2 - 4x - 6x + 24) = x[ x(x - 4) - 6(x - 4) ] = x(x - 6)(x - 4)
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
What is the LCM of x2 plus 4x and x2-4x?
x(x + 4)(x - 4) or x3 - 16x
What is x plus 4 divided by x3 -11x plus 20?
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
Factor x3 plus 64?
64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)
How do you factor x3 plus 3x2-4x-12?
x3 + 3x2 - 4x -12 x2(x + 3) - 4(x + 3) (x2 - 4)(x+3)
What is the quotient and remainder if any when the expession 4x4 -x3 plus 17x2 plus 11x plus 4 is divided by 4x plus 3?
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
What is the factor of X3 - 2x2 - 4x plus 8?
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
X3 plus 6x2 - 4x - 24 factor completely?
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
What is the quotient and remainder of 4x4 -x3 plus 17x2 plus 11x plus 4 when divided by 4x plus 3?
Dividend: 4x^4 -x^2 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
How do you factor x3-3x2 plus 4?
x3 - 3x2 + 4 Since the coefficients of the odd powers of x (=1) is the same as the sum of the even powers (-3+4=1), then x = -1 must be a root. That is to say, (x + 1) is a factor. So you can rewrite the expression as x3 + x2 - 4x2 - 4x + 4x + 4 = x2(x + 1) - 4(x + 1) + 4(x + 1) = (x + 1)*(x2 - 4x + 4) = (x + 1)*(x - 2)2
