(y - 4)(y - 8)
4x2-y2 = (2x-y)(2x+y)
y2 + y2 - 56 let's factor it such as = 2y2 - 56 = 2(y2 - 28) = 2[y2 - (√28)2] = 2(y - √28)(y + √28) = 2(y - √4*7)(y + √4*7) = 2(y - 2√7)(y + 2√7)
4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2
This is not factor-able.
y4 - 256 = (y2 - 16)(y2 + 16) = (y - 4)(y + 4)(y2 + 16)
y(y + 4)
x2 -y2 +4y-4=(x+y)(x-y)+4y-4
4 - y2 can be written as 22 - y2. This has become of the form of x2 - y2.Expansion for x2 - y2 is (x+y)(x-y).So, 4 - y2 = 22 - y2 = (2+y)(2-y)
(y - 1)(y - 4)
(y - 4)(y - 8)
y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2
(y + 5)(y - 4)
It is: y2
-x2(y - 2)(y + 2)(y2 + 4)
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
4x2-y2 = (2x-y)(2x+y)