45
The integers are 40, 41 and 42.
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
38, 39, 40
No consecutive integers add up to 40. The closest would be 42, adding 13,14 and 15.
The numbers are 37, 38, 39 and 40.
No. There is no set of three consecutive even integers with a sum of 40.
The integers are 39 and 40.
The integers are 40, 41 and 42.
They are -41 and -40.
They are 40, 41 and 42.
40, 41, 42, and 43 are.
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.
The consecutive odd integers for 114 are 37, 38 and 39.
Half it = 41, so consecutive even integers are 40 & 42
The numbers are 39 and 40.
38, 39, 40