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Q: What is cos of 2 theta?

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- cos theta

(/) = theta sin 2(/) = 2sin(/)cos(/)

Tan^2

You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.

sin/cos

Related questions

Cos theta squared

Let 'theta' = A [as 'A' is easier to type] sec A - 1/(sec A) = 1/(cos A) - cos A = (1 - cos^2 A)/(cos A) = (sin^2 A)/(cos A) = (tan A)*(sin A) Then you can swap back the 'A' with theta

It's 1/2 of sin(2 theta) .

- cos theta

(/) = theta sin 2(/) = 2sin(/)cos(/)

4*cos2(theta) = 1 cos2(theta) = 1/4 cos(theta) = sqrt(1/4) = Â±1/2 Now cos(theta) = 1/2 => theta = 60 + 360k or theta = 300 + 360k while Now cos(theta) = -1/2 => theta = 120 + 360k or theta = 240 + 360k where k is an integer.

cos2(theta) = 1 so cos(theta) = Â±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0

'csc' = 1/sin'tan' = sin/cosSo it must follow that(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2

Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).

because sin(2x) = 2sin(x)cos(x)

Tan^2

cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1

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