x2 + 4x - 3 = 0 add 3 to both sides
x2 + 4x = 3 add 22 to both sides to complete the square
x2 + 4x + 22 = 7 form the square
(x + 2)2 = 7 take the square root of both sides
x + 2 = ± √7 subtract 2 to both sides
x = -2 ± √7
x = -2 + √7 or x = -2 - √7
Solve using the quadratic formula
It is: 3x2+6x-11 = 0
That factors to (a + 1)(a + b) a = -1, -b b = -a
(x-3)(x-2)
(x - 3)(x + 5)
Solve using the quadratic formula
It is: 3x2+6x-11 = 0
That factors to (a + 1)(a + b) a = -1, -b b = -a
X=1
(x-3)(x-2)
(x - 3)(x + 5)
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal
x = 25 / 3squared + 5
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104
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
Not sure how to put it. The Pythagorean therom states that a squared plus b squared equals c squared. Aren't a, b and c all variables?