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What is the sum of the first 4 multiples of 6?
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
What is the sum of the first 500 multiples of 6?
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
What is the sum of the first 5 multiples of 6?
90
What is the sum of the first 4 multiples of 5?
5 + 10+15+20=50 ans
What is the sum of the first three multiples of 6?
It is: 6+12+18 = 36
The sum of three consecutive multiples of 6 is 666find the multiples?
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
What is the sum of the first 2 multiples of 6?
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
What is the sum of first 15 multiples of 6?
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.
What is the sum of the first five multiples of 6?
6+12+18+24+30=90
What are the first 3 multiples of 6 and 10?
30, 60, 90
What are the first 2 common multiples of 6 and 15?
30 and 60
What are the first five common multiples of five and six?
First three common multiples of 5 and 6 are 30, 60 and 90.
