It's an equation that's sitting there begging us to find what values for Θ make it
a true statement.
For the first few moments, just to make it simpler to look at and to write, I'll
call cos(Θ) by the name 'C'.
You said that [ 2C2 - C = 1 ]
Subtract 1 from each side: [ 2C2 - C - 1 = 0 ]
This is a plain old quadratic equation.
When you factor it, it becomes . . . . . . (2C + 1) (C- 1) = 0
Setting each factor to zero in turn, you get the two roots:
C = 1
C = - 1/2
Now we can go back to the trig world:
cos(Θ) = C
cos(Θ) = 1 . . . . . Θ = any positive or negative multiple of 360° .
cos(Θ) = - 1/2 . . . Θ = (any positive or negative multiple of 360°) plus or minus 120° .
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
Zero. Anything minus itself is zero.
1
The question contains an expression but not an equation. An expression cannot be solved.
4*cos2(theta) = 1 cos2(theta) = 1/4 cos(theta) = sqrt(1/4) = ±1/2 Now cos(theta) = 1/2 => theta = 60 + 360k or theta = 300 + 360k while Now cos(theta) = -1/2 => theta = 120 + 360k or theta = 240 + 360k where k is an integer.
Tan^2
Cos theta squared
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
Zero. Anything minus itself is zero.
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
cosine (90- theta) = sine (theta)
cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1
1
The question contains an expression but not an equation. An expression cannot be solved.
4*cos2(theta) = 1 cos2(theta) = 1/4 cos(theta) = sqrt(1/4) = ±1/2 Now cos(theta) = 1/2 => theta = 60 + 360k or theta = 300 + 360k while Now cos(theta) = -1/2 => theta = 120 + 360k or theta = 240 + 360k where k is an integer.