0
It's an equation that's sitting there begging us to find what values for Θ make it
a true statement.
For the first few moments, just to make it simpler to look at and to write, I'll
call cos(Θ) by the name 'C'.
You said that [ 2C2 - C = 1 ]
Subtract 1 from each side: [ 2C2 - C - 1 = 0 ]
This is a plain old quadratic equation.
When you factor it, it becomes . . . . . . (2C + 1) (C- 1) = 0
Setting each factor to zero in turn, you get the two roots:
C = 1
C = - 1/2
Now we can go back to the trig world:
cos(Θ) = C
cos(Θ) = 1 . . . . . Θ = any positive or negative multiple of 360° .
cos(Θ) = - 1/2 . . . Θ = (any positive or negative multiple of 360°) plus or minus 120° .
What else can I help you with?
What divided by cosine squared theta equals one?
The equation that satisfies the condition "what divided by cosine squared theta equals one" is simply the expression itself. If we let ( x ) be the quantity, then the equation can be expressed as ( \frac{x}{\cos^2 \theta} = 1 ). Solving for ( x ) gives ( x = \cos^2 \theta ). Thus, ( \cos^2 \theta ) divided by ( \cos^2 \theta ) equals one.
How do you prove cot squared theta plus cos squared theta plus sin squared theta scs squared theta?
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
What is Cos Theta minus Cos Theta?
Zero. Anything minus itself is zero.
Sin squared theta plus cos squared theta barabar Kya Hota Hai?
1
How do you solve cos theta subtract cos squared theta divide 1 plus cos theta?
The question contains an expression but not an equation. An expression cannot be solved.
What is sec squared theta times cos squared theta minus tan squared theta?
Sec^(2) = 1 / Cos^(2) Hence Sec^(2) X Cos^(2) = 1/Cos^(2) X Cos^(2) Cancel down by ' Cos^(2) '. 1/1 X 1 = 1 1 - Tan^(2) (The ANSWER) !!!!! Factor ( 1 - Tan)(1 + Tan)
What is cos theta times cos theta?
Cos(Theta) X Cos(Theta) = Cos^(2)[Theta].
What divided by cosine squared theta equals one?
The equation that satisfies the condition "what divided by cosine squared theta equals one" is simply the expression itself. If we let ( x ) be the quantity, then the equation can be expressed as ( \frac{x}{\cos^2 \theta} = 1 ). Solving for ( x ) gives ( x = \cos^2 \theta ). Thus, ( \cos^2 \theta ) divided by ( \cos^2 \theta ) equals one.
How do you solve theta if cos squared theta equals 1 and 0 is less than or equal to theta which is less than 2pi?
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
How do you prove cot squared theta plus cos squared theta plus sin squared theta scs squared theta?
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
What is Cos Theta minus Cos Theta?
Zero. Anything minus itself is zero.
What is cos theta minus cos theta times sin squared theta?
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
How would you solve and show work for cos2 theta if cos squared theta equals 1 and theta is in the 4th quadrant?
cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1
What does negative sine squared plus cosine squared equal?
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
What is cos 90 minus theta?
cosine (90- theta) = sine (theta)
Sin squared theta plus cos squared theta barabar Kya Hota Hai?
1
How do you solve cos theta subtract cos squared theta divide 1 plus cos theta?
The question contains an expression but not an equation. An expression cannot be solved.
