It's an equation that's sitting there begging us to find what values for Θ make it
a true statement.
For the first few moments, just to make it simpler to look at and to write, I'll
call cos(Θ) by the name 'C'.
You said that [ 2C2 - C = 1 ]
Subtract 1 from each side: [ 2C2 - C - 1 = 0 ]
This is a plain old quadratic equation.
When you factor it, it becomes . . . . . . (2C + 1) (C- 1) = 0
Setting each factor to zero in turn, you get the two roots:
C = 1
C = - 1/2
Now we can go back to the trig world:
cos(Θ) = C
cos(Θ) = 1 . . . . . Θ = any positive or negative multiple of 360° .
cos(Θ) = - 1/2 . . . Θ = (any positive or negative multiple of 360°) plus or minus 120° .
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
Zero. Anything minus itself is zero.
1
The question contains an expression but not an equation. An expression cannot be solved.
4*cos2(theta) = 1 cos2(theta) = 1/4 cos(theta) = sqrt(1/4) = ±1/2 Now cos(theta) = 1/2 => theta = 60 + 360k or theta = 300 + 360k while Now cos(theta) = -1/2 => theta = 120 + 360k or theta = 240 + 360k where k is an integer.
Tan^2
Cos theta squared
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
- cos theta
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
Zero. Anything minus itself is zero.
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1
cosine (90- theta) = sine (theta)
1
The question contains an expression but not an equation. An expression cannot be solved.