There are an infinite number of equations that could have 9 and 7 as answers. Just one example (and an easy one) might be: x2 - 16x + 63 = 0 (x - 9) x (x - 7) = 0 (x - 9) = 0, x = 9 (x - 7) = 0, x = 7
how many solutions does the equation have? 4x+1=5+2(2-4) a. one solution b. infinite solutions c. no solution
x2 - 12x + 35
4x + 7 is an expression, not an equation. Only an equation (or an inequality) can have solutions, an expression cannot have a solution.
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
1 is the answer
how many solutions does the equation have? 4x+1=5+2(2-4) a. one solution b. infinite solutions c. no solution
10
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
x2 - 12x + 35
None because without an equality sign the given expression is not an equation and so therefore no solutions are possible.
4x + 7 is an expression, not an equation. Only an equation (or an inequality) can have solutions, an expression cannot have a solution.
There are infinitely many solutions to 11x - 99 = 11(x - 9)
No. It's a quadratic equation, and it has two solutions.
-3
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
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