Without an equality sign the expression given can't be considered to be an equation.
the problem is not proper to slove. I just want to suggest to follow the related link that explains the concept of completing the square clearly.
No because the discriminant of the given quadratic expression is less than zero.
I assume you mean the equation 2x2 + 12x - 10 = 0. Divide by 2: x2 + 6x - 5 = 0 To complete the square, the constant part (the part with no variable) must be half the linear part (1/2 of 6), squared, so in this case you add 14 to each side: x2 + 6x +9 = 14 This can be factored: (x+3)2 = 14 Now, just take the square root of each side: x + 3 = (plus-or-minus) 14 Solve the resulting two equations (one for plus, one for minus).
x2 + 20x +0 =30 [(20/2)2 =100] x2 + 20x + 100 =30 +100 √(x+10)2=√130 x+10=√130 x= −10+√130 √ means square root
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
please help on this x2+6x+27=
Um.......is it x2+6x or x2-6x. I think your missing some things here champ
x2+6x-7 = 0 (x+3)2-7 = 0 (x+3)2-7-9 = 0 (x+3)2 = 16 x+3 = + or - 4 x = - 3 + or - 4 x = 1 or -7
Without an equality sign the expression given can't be considered to be an equation.
the problem is not proper to slove. I just want to suggest to follow the related link that explains the concept of completing the square clearly.
If: x2-6x-13 = 14 Then: x2-6x-27 = 0 And: (x+3)(x-9) = 0 So: x = -3 or x = 9
If you aren't dealing with algebra, such as x2+3x+21, then completing the square wont be able to solve the porblem, however if you are using algebra, and you cannot factorise, then completing the square will always work
x2 - 6x = 16 ∴ x2 - 6x + 9 = 25 ∴ (x - 3)2 = 25 ∴ x - 3 = 25 ∴ x = 28
2x+6x=-9 => 8x=-9=> x=-8/9
No because the discriminant of the given quadratic expression is less than zero.