answersLogoWhite

0

First we look at the double-angle identity of cos2x.

We know that:

cos2x = cos^2x - sin^2x

cos2x = [1-sin^2x] - sin^2x.............. (From sin^2x + cos^2x = 1, cos^2x = 1 - sin^2x)

Therefore:

cos2x = 1 - 2sin^2x

2sin^2x = 1 - cos2x

sin^2x = 1/2(1-cos2x)

sin^2x = 1/2 - cos2x/2

And intergrating, we get:

x/2 - sin2x/4 + c...................(Integral of cos2x = 1/2sin2x; and c is a constant)

User Avatar

Wiki User

12y ago

Still curious? Ask our experts.

Chat with our AI personalities

FranFran
I've made my fair share of mistakes, and if I can help you avoid a few, I'd sure like to try.
Chat with Fran
ReneRene
Change my mind. I dare you.
Chat with Rene
BeauBeau
You're doing better than you think!
Chat with Beau

Add your answer:

Earn +20 pts
Q: Integral of sin squared x
Write your answer...
Submit
Still have questions?
magnify glass
imp