tan theta = sqrt(2)/2 = 1/sqrt(2).
If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
Your question is CscΘ=? when SinΘ=2/3 in Q1 well bases on the fundamental identities.. Sin Θ= 1/CscΘ and CscΘ= 1/SinΘ So when your in is 2/3 CscΘ=1/sinΘ CscΘ =1/(2/3) CscΘ = 3/2 -The value of cscΘ and it is positive because all functions in quadrant 1 are positive.. If you have more questions, please comment..:))
The fourth Across the quadrants sin theta and cos theta vary: sin theta: + + - - cos theta: + - - + So for sin theta < 0, it's the third or fourth quadrant And for cos theta > 0 , it's the first or fourth quadrant. So for sin theta < 0 and cos theta > 0 it's the fourth quadrant
Yes. (Theta in radians, and then approximately, not exactly.)
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
0.75
If tan theta equals 2, then the sides of the triangle could be -2, -1, and square root of 5 (I used the Pythagorean Theorem to get this). From this, sec theta is negative square root of 5. It is negative because theta is in the third quadrant, where cosine, secant, sine, and cosecant are all negative.
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
tan theta = sqrt(2)/2 = 1/sqrt(2).
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.
cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1
It is -sqrt(1 + cot^2 theta)
It means that 0 < theta < pi/2 radians or 90 degrees.
The angles in quadrant one measure between 0 degrees and 90 degrees. In radians, that's between 0 and pi/2. Quadrant one is the quadrant where both X and Y (or cosine theta and sine theta) are positive.
If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
Your question is CscΘ=? when SinΘ=2/3 in Q1 well bases on the fundamental identities.. Sin Θ= 1/CscΘ and CscΘ= 1/SinΘ So when your in is 2/3 CscΘ=1/sinΘ CscΘ =1/(2/3) CscΘ = 3/2 -The value of cscΘ and it is positive because all functions in quadrant 1 are positive.. If you have more questions, please comment..:))