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Assuming that the digits 0-9 are available, the answer is 5040. This is because for the first digit you can pick any of the original 10 digits. For the second you can have any otherdigit, so 9 possible choices. The third follows the same rule, so has 8 possibilities, and the forth digit, 7.
This means that the total number of combinations is 10 x 9 x 8 x 7 = 5040
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How many 5 digit number combinations from 1 to 60slide1?
There are 5,461,512 such combinations.
How many combinations are there for a four digit number?
64
How many 3 digit number combinations can be made from 764?
6 of them.
How many 3 digit combinations are there in 1 to 21?
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
How many two digit combinations for number 1 through 9?
44
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