sin2(1) = 1 - cos2(1) = 1 - [cos(1)]2
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(sin x + cos x) / cosx = sin x / cos x + cosx / cos x = tan x + 1
The deriviative of sin2 x + cos2 x is 2 cos x - 2 sin x
The answer is 1. sin^2 x cos^2/sin^2 x 1/cos^2 cos^2 will be cancelled =1 sin^2 also will be cancelled=1 1/1 = 1
(1+cosx)(1-cosx)= 1 +cosx - cosx -cos^2x (where ^2 means squared) = 1-cos^2x = sin^2x (sin squared x)
To simplify such expressions, it helps to express all trigonometric functions in terms of sines and cosines. That is, convert tan, cot, sec or csc to their equivalent in terms of sin and cos.