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sin2(1) = 1 - cos2(1) = 1 - [cos(1)]2

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Q: How to express Sin squared 1 in terms of cos 1?
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Factor sin cubed plus cos cubed?

sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)


What is tan squared theta minus sec squared theta simplified?

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How do you prove that the sin over one minus the cosine minus one plus the cosine over the sine equals zero?

Multiply both sides by sin(1-cos) and you lose the denominators and get (sin squared) minus 1+cos times 1-cos. Then multiply out (i.e. expand) 1+cos times 1-cos, which will of course give the difference of two squares: 1 - (cos squared). (because the cross terms cancel out.) (This is diff of 2 squares because 1 is the square of 1.) And so you get (sin squared) - (1 - (cos squared)) = (sin squared) + (cos squared) - 1. Then from basic trig we know that (sin squared) + (cos squared) = 1, so this is 0.


What is sin squared x minus cos squared x?

Sin squared, cos squared...you removed the x in the equation.


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Sin squared is equal to 1 - cos squared.


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What does 1 - cos squared equal?

Note that an angle should always be specified - for example, 1 - cos square x. Due to the Pythagorean formula, this can be simplified as sin square x. Note that sin square x is a shortcut of (sin x) squared.


How do you differentiate sin squared x plus cos squared x?

The deriviative of sin2 x + cos2 x is 2 cos x - 2 sin x