To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
To simplify the expression (12r + 5 + 3r - 5), combine like terms. First, combine the (r) terms: (12r + 3r = 15r). Then, combine the constant terms: (5 - 5 = 0). Thus, the simplified expression is (15r).
5
8
They are -2, 2, 6, 10 and 14.
5
it is 8.
5 first terms in n²+3
2
5
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
5, 11, 17, 23, 29
4,8,12,16,20
8
They are -2, 2, 6, 10 and 14.
They are: 6 15 24 33 and 42