To find the first five terms of the expression ( f(x)f(x-1)x^3 ), we need to know the specific function ( f(x) ). Assuming ( f(x) ) is a polynomial or can be expressed in a series expansion (like a Taylor series), we would substitute ( f(x) ) and ( f(x-1) ) into the expression and then multiply by ( x^3 ). Without specific details about ( f(x) ), I cannot provide the exact terms. Please provide ( f(x) ) for a more accurate answer.
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
To simplify the expression (12r + 5 + 3r - 5), combine like terms. First, combine the (r) terms: (12r + 3r = 15r). Then, combine the constant terms: (5 - 5 = 0). Thus, the simplified expression is (15r).
5
8
5
it is 8.
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
To simplify the expression (12r + 5 + 3r - 5), combine like terms. First, combine the (r) terms: (12r + 3r = 15r). Then, combine the constant terms: (5 - 5 = 0). Thus, the simplified expression is (15r).
5 first terms in n²+3
2
20, 15, 10, 5, 0, -5, -10, -15, -20 and so on.
5
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.
5, 11, 17, 23, 29
4,8,12,16,20
They are -2, 2, 6, 10 and 14.