Around 17.8. I did this with cossin, but check the answer with a calculator
43.26661530556787
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
Perimeter of [ 16 x 26 ] rectangle = 16 + 16 + 26 + 26 = 84-ft . Perimeter of a 20-ft square = 4 x 20 = 80-ft . The rectangle has the greater perimeter.
20 ft
18.9 feet
Using Pythagoras' theorem it is 40 feet
18.9 feet
Around 17.8. I did this with cossin, but check the answer with a calculator
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. In this case, the diagonal forms the hypotenuse of a right triangle with the sides being the length and width of the rectangle. So, the diagonal (d) can be calculated as d = √(4^2 + 6^2) = √(16 + 36) = √52 ≈ 7.21 feet.
114.826 ft
43.26661530556787
To find the answer, use Pythagorean theorem. You have a and b, and want c. c=square root of 16 squared plus 24 squared = 28.8444
57.3062 ft
97.617 ft
diagonal = sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 5.6568