sqrt(1152)
The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
The length of the diagonal of an ( a , \text{ft} \times a , \text{ft} ) rectangle can be calculated using the Pythagorean theorem. The diagonal ( d ) is given by the formula ( d = \sqrt{a^2 + a^2} = \sqrt{2a^2} = a\sqrt{2} ). Therefore, the length of the diagonal is ( a\sqrt{2} ) feet.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
The diagonal is 33.941 units.
114.826 ft
35.384 ft (rounded)
43.26661530556787
36.8782 ft
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
46.648 ft
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
The diagonal is ~16.97 feet.
The diagonal measurement of an 8 ft square is: 11.31 feet.
To find the answer, use Pythagorean theorem. You have a and b, and want c. c=square root of 16 squared plus 24 squared = 28.8444
The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
60.28 is the length of the diagonal, got through Pythagoras' Theorem.
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft