Two adjacent sides of a square and the diagonal joining their ends froms a right angle triangle. The legs of the triangle are 10 ft each and the diagonal is the hypotenuse. By pythagoras, diagonal = sqrt(102 + 102) = 10*sqrt(2) = 14.142 ft (to 3 dp).
The perimeter of a square with a diagonal of 12 centimeters is: 33.9 centimeters.In future, to find out the perimeter of a square when you only know it's diagonal, use Pythagoras or times the diagonal by 2.828427125.This number is irrational, and is like a pi for the diagonals of squares.I call it Tau.It is the relationship between the diagonal of all squares and there perimeter.
12 ft * 12 ft = 4 yd * 4 yd = 16 sq yards
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
Approximately 17 feet.
14 ft
The diagonal measurement of an 8 ft square is: 11.31 feet.
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
1 ft = 12 in Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 → side = diagonal ÷ √2 perimeter = 4 × side = 4 × diagonal ÷ √2 = diagonal × 2√2 = 3 ft 9 in × 2√2 = 3 × 12 + 9 in × 2√2 = 45 in × 2√2 ≈ 63.6 in = 5 × 12 + 3.4 in = 5 ft 3.4 in
The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
The diagonal of a 46' x 46' square is 65.05 feet.
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
18 ft Diagonal of a square is the square root of 2, times the side.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.